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find the vertex of the parabola
y^2=2x^2-10x+3

2007-05-21 19:47:24 · 4 answers · asked by bgonzii 2 in Science & Mathematics Mathematics

4 answers

This is the equation of a hyperbola, not a parabola. This has vertices when y = 0, ie. when

2 x^2 - 10x + 3 = 0.

Solve this quadratic, and then, if the roots are a and b, you vertices are at (a, 0) and (b, 0).

2007-05-21 20:14:53 · answer #1 · answered by MHW 5 · 0 0

y^2=2x^2-10x+3
This is not the equation of a parabola.

2007-05-21 20:14:07 · answer #2 · answered by ironduke8159 7 · 0 0

That equation describes a hyperbola, not a parabola.

2007-05-21 20:06:53 · answer #3 · answered by Brent L 5 · 1 0

Vertex is where x = 0. Substitute 0 for all x and solve for y.

2007-05-21 19:56:56 · answer #4 · answered by Anonymous · 0 2

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