Find the radius of the circle
x^2 +2x+y^2-6y=12
2007-05-21 19:46:00 · 5 answers · asked by bgonzii 2 in Science & Mathematics ➔ Mathematics
x^2+2x+y^2-6y=12
=>(x^2+2x+1)+(y^2-6y+9)=12+1+9
=>(x+1)^2+(y-3)^2=22=(4.69)^2
Therefore,the radius of the circle is 4.69
2007-05-21 20:03:26 · answer #1 · answered by alpha 7 · 0⤊ 0⤋
The radius is the x^2 and y^2 coefficient.
2007-05-21 19:54:47 · answer #2 · answered by Anonymous · 0⤊ 0⤋
x² + y² + 2x - 6y - 12 = 0 (equation of circle)
x² + y² + 2gx + 2fy + c = 0 (standard equation)
2g = 2
g = 1
2f = - 6
f = - 3
c = - 12
r = √(g² + f² - c)
r =√(1 + 9 + 12)
r = √22
2007-05-22 07:48:02 · answer #3 · answered by Como 7 · 0⤊ 0⤋
22^1/2
2007-05-21 20:28:12 · answer #4 · answered by yoshita_nandamuri 2 · 0⤊ 0⤋
the formula to find the radius of a circle is
square root of [(g^2)+(f^2)+c]
which is square root of (22)
4.69
2007-05-21 21:53:21 · answer #5 · answered by Harish R 2 · 0⤊ 0⤋