A 325.0g piece of gold at 427 degree c is dropped into 200.0mL of water at 22.0degree c. Calculate the final?

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A 325.0g piece of gold at 427 degree c is dropped into 200.0mL of water at 22.0degree c. Calculate the final?

temperature of the mixture. Specific Heat of gold = 0.131 J/g degree celsius. (2 component). Please help

2007-05-21 17:09:28 · 1 answers · asked by southerngold26 1 in Science & Mathematics ➔ Chemistry

1 answers

Heat given up by gold= heat gained by water
If X is the final temperature.
Wgold x Cp x 427-X degrees = 200 x 4.184J/gdegC x X-22. Substitute and solve.

2007-05-21 17:19:04 · answer #1 · answered by cattbarf 7 · 1⤊ 0⤋