if were given a chord of a circle..
how can we construct a chord thats parallel but 1/2 length of the given?
2007-05-21 16:54:53 · 3 answers · asked by uhohspaghettiohohs 5 in Science & Mathematics ➔ Mathematics
anyone know how to do that?
2007-05-21 17:17:50 · update #1
Dissect the chord, then dissect each half of the chord. Draw lines perpendicular to each of these midpoints through the perimeter of the circle, then connect these two points to make your new chord.
A picture would be worth a thousand words...
2007-05-21 17:54:09 · answer #1 · answered by Anonymous · 0⤊ 0⤋
One construction (which is a bit inelegant, someone might be able to suggest a simpler one) is as follows: let the chord be AB. Bisect it at C, and then draw the perpendicular bisectors of AC and CB. Call the perpendicular bisector of AC â and the perpendicular bisector of CB m. Then let D be a point of intersection of â and the circle and E be the point of intersection of m and the circle that is on the same side of AB as D. Then DE will be a chord of the circle that is 1/2 the length of AB.
2007-05-22 00:45:03 · answer #2 · answered by Pascal 7 · 0⤊ 0⤋
You'd have to calculate how much farther down the radius to go to get 1/2 lenght. After that, draw a parallel line.
2007-05-22 00:06:04 · answer #3 · answered by samswebsite 4 · 0⤊ 0⤋