9x^2+16y^2=144
3x^2+4y^2=36
(i got 13.64 is this right?)
2007-05-21 16:23:17 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
multiply the 2nd equation by -3
9x^2 + 16y^2 = 144
-9x^2 - 12y^2 = -108
add the 2 equations together
4y^2 = 36
divide by 4
y^2 = 9
square root
y= +/- 3
plug back in to find x
x=0
2007-05-21 16:29:04 · answer #1 · answered by Anonymous · 1⤊ 0⤋
9x² + 16y² = 144
- 9x² - 12y² = - 108
4y² = 36
y² = 9
y = ± 3
3x² + 36 = 36
x = 0
Solution is (0,3) , (0,-3)
2007-05-22 03:12:36 · answer #2 · answered by Como 7 · 0⤊ 0⤋
Nope. Multiply everything on the bottom by -3 and then add the equations together. You get rid of the x variable and then solve for y. After you have y, plug it into one of the equations to find x.
2007-05-21 23:36:29 · answer #3 · answered by kd 1 · 0⤊ 1⤋
Just solve for x² and y² the same as you would any other system of linear equations. You'll get
x² = a and
y² = b so that
x = âa and
y = âb are the values for x and y
HTH
Doug
2007-05-21 23:29:19 · answer #4 · answered by doug_donaghue 7 · 0⤊ 1⤋