simplify the rational expression. Find the excluded values.
x-6
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x^2-36
2007-05-21 16:17:00 · 8 answers · asked by nikkecola17 3 in Science & Mathematics ➔ Mathematics
(x-6)
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(x-6)(x+6)
1
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(x+6)
2007-05-21 16:20:19 · answer #1 · answered by untitledonald 2 · 0⤊ 0⤋
= (x - 6) / ((x - 6).(x + 6))
= 1 / (x + 6)
Excluded values are x = - 6, x = 6
2007-05-21 20:22:37 · answer #2 · answered by Como 7 · 0⤊ 0⤋
1
----
x+6
=]
2007-05-21 16:25:51 · answer #3 · answered by ? 4 · 0⤊ 0⤋
so on the bottom you have: (x-6)(x+6). the 2 x-6s cancel out, you're left with (x+6)
2007-05-21 16:20:53 · answer #4 · answered by omygosh 4 · 0⤊ 0⤋
n solve
(x= x - 6/ x^2-36 , {x} )
x~ 0.1622776601684
i just don't know... is this right?..
2007-05-21 16:32:25 · answer #5 · answered by ô,ô 2 · 0⤊ 0⤋
x-6
------
(x+6)(x-6)
1
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(x+6)
2007-05-21 16:25:31 · answer #6 · answered by K R 2 · 0⤊ 0⤋
(x-6)
---------
(x-6)(x+6)
1
----
(x+6)
2007-05-21 16:28:27 · answer #7 · answered by perla0776 4 · 0⤊ 0⤋
(x-6)
-------------
(x-6)(x+6)
1
------
(x+6)
the excluded value, which would make it undefined...
x + 6 = 0
x = -6
^.^
2007-05-21 16:28:49 · answer #8 · answered by Anonymous · 2⤊ 0⤋