solve the system of equations 3x+2y=17, 2x-y=9?

Answer 1

The basic procedure with these problems is to solve one equation for one variable, substitute that into the second equation, solve for the second variable, substitute that into the first equation, and solve for the first variable.

Since the second equation has a lone y in it, I think I'd start by solving it for y -- y = 2x-9. Put that in the first equation and solve:
3x + 2*(2x-9) = 17
3x + 4x - 18 = 17
7x - 18 = 17
7x = 35
x = 5

Now that you know x, put it in the second equation and solve for y.

2*(5) - y = 9
10 - y = 9
10 = 9 + y
10 - 9 = y
y = 1

So the answer should be x=5, y=1. Adding or subtracting the two equations together can work, too, and is sometimes easier in certain cases. But at least when I was taught, this was the standard procedure used. I hope this helps.

Answer 2

3x+2y=17- (1) 2x-y=9 - (2) Multiply 2nd equation by 2 and add it to the first. (1) - 3x+2y=17 (2) - 4x-2y =18 7x = 35 x = 5 Substitute x value into second and solve for y ( 2)- 2*5 - y = 9 -y = -1 y = 1

Answer 3

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solve the system of equations 3x+2y=17, 2x-y=9?

Answer 4

3x +2y =17 --(1)
2x-y =9 --(2)
From equation2, make y the subject
y=2x -9 --(3)
Substitute equation 3 into equation1,
3x +2(2x-9) = 17
3x +4x-18 =17
7x = 35
x = 5

SInce x=5,
y=2(5)-9 =1

Answer 5

First re-distribute 2x-y = 9 to y=2x -9
substitute for y 3x + 2(2x -9) = 17 , solve 3x + 4x -18 =17 or
7x =35 hence x = 5

Plug in y =2(5) - 9 , therefor y =1

Check 3(5) + 2(1) = 17 Solution is x= 5 , y = 1

Answer 6

I love simultaneous equations

Lets do this one by the elimination method

3x + 2y = 17 (that's your first one)
4x - 2y = 18 (that's your second one - I've multiplied it all by 2)

add them together (cos if the LHS = RHS then you can add them)

7x + 0y = 35

7x = 35

Solve for x

Put that back into one of the equations

Like ... 2x - y = 9

So y = 2x - 9

You know what x is.

Solve for y

Give your answer to the teacher!

Answer 7

2x - y = 9
-y = - 2x + 9
y = 2x - 9 then substitute

3x + 2(2x - 9) = 17
3x + 4x - 18 = 17
7x = 35
x = 5 now u have value of x, then substitute in for x

2x - y = 9
2(5) - y = 9
10 - y = 9
1 = y
ok , good luck

Answer 8

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Isolate "x" or "y" in either equation. Let's isolate "x" in the 1st equation. First: subtract 2y from both sides (when you move a term to the opposite side, always use the opposite sign). 3x+2y-2y = 17-2y 3x = 17-2y (divide each term by 3). 3x/3 = 17/3 - 2y/3 x = 17/3 - 2y/3 Sec: substitute 17/3 -2y/3 with "x" in the 2nd equation. 2(17/3 - 2y/3) - 1y = 9 34/3 - 4y/3 - 1y = 9 34/3 - 7/3y = 9 (subtract 34/3 from both sides). 34/3 -34/3 - 7y/3 = 9-34/3 -7y/3 = -7/3 (multiply both sides by -3/7). (-3/7)(-7y/3) = (-3/7)(-7/3) y = 21/21 y = 1 Third: substitute 1 with "y" in the 1st equation. 3x+2(1) = 17 3x+2 = 17 (subtract 2 from both sides). 3x+2-2 = 17-2 3x = 15 (divide both sides by 3). 3x/3 = 15/3 x = 5 Solutions set: (5, 1)

Answer 9

3x+2y=17(1st ) , 2x-y=9(2nd)
(multiply the 2nd equation with 2)
2(2x-y=9) =>4x-2y=18(3rd)
now add 1st & 3rd equation
3x+2y=17
4x -2y=18
=>7x=35(2y-2y gets cancelled)
=>x=35/7
=>x=5
therefore x =5
now substitute value of x in 2nd equation to get the value of y
2x-y=9
2(5)-y=9
10-y=9
y=1

Answer 10

y=2x-9
3x + 2(2x-9)=17
3x+4x-18=17
7x=35
x=5
y=2(5)-9
y=1
(5,1) mean x=5 and y=1