We have a solution of benzoic acid, C6H5CO2H. What is the effect of adding sodium hydroxide to this solution?
1. The pH increases.
2. The concentration of C6H5CO2H decreases.
3. The concentration of H3O+ increases.
a. 1 only
b. 2 only
c. 3 only
d. 1 and 2
e. 2 and 3
2007-05-21 15:25:44 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
C6H5COOH + OH- >> C6H5COO- + H2O
pH increases
and [C6H5COOH ] decreases
d.
2007-05-21 19:23:18 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Somehow, I feel like Elmo. Letter d.
2007-05-21 15:30:10 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋
pKa = ( [H+] x [HCOO-] ) / [HCOOH] entire volume of the answer = eighty ml [HCOOH] = ( 0.04 lit x 0.25 mole/lit ) / 0.08 lit = 0.a hundred twenty five M [HCOO-] = (0.04 lit x 0.25 mole/lit ) / 0.08 lit = 0.a hundred twenty five M The pKa that's reported in the question isn't basically right suited ! pKa < a million
2016-12-11 16:39:00 · answer #3 · answered by ? 4 · 0⤊ 0⤋