whats the square root of -36a^4?

Question

i feel like im asking too many questions.

i hate math and i dont understand this whole "i" concept!!!

Answer 1

please don't hate math >.<
it's 6a^2i
what's wrong with the i concept?
it's just i^2 = -1, -i^2 = 1, -i = -sqrt(-1), ...
i'm not angry or anything.
i just don't want anyone to hate math.
^.^

Answer 2

square root -36a^4
= squareroot (-1)(36a^4)
=squareroot (-1)*squareroot 36a^4
=squareroot (-1)*6a^2
Now the squareroot of -1 is defined to be i, which stands for imaginary. So the final answer is i6a^2, which is a pure imaginary number.

a numbe such as 4+i3 is a complex number because it has a real part (the 4) and an imaginary part (the i3).

Complex numbers play an important role in advanced mathematics. You should know that:
i = sqrt(-1)
i^2 = -1
i^3 = -i
and i^4 = 1.

Answer 3

the whole 'i' thing doesnt need to be so complicated. simply stated i is defined as the square root of -1...which means that i^2=-1

with that in mind, to find the square root of -36a^4 seperate the terms and find the square root of each in the product.

sqrt(-36a^4) = sqrt(-1 * 36 * a^4) wher the * is meant to denote multiplication.
sqrt(-1 * 36 * a^4) = sqrt(-1)*sqrt(36)*sqrt(a^4)
= i * 6 * a^2, so sqrt(-36a^4) = i36a^2

dont feel like your asking too many questions...thats what this is for. if you dont understand something its better to ask people who can help you than to waste your time being frustrated

Answer 4

It is 6a^2*i

The idea behind i is to give a way to do square roots of negative numbers. i is the square root of -1. Don't worry, if you keep going on in math, it doesn't come back for a long while.

Answer 5

- 36a^4
= (36 i²).a^4------(noting that i² = - 1)
Taking square root gives:-
6 i x a² = i 6a²

Answer 6

6a^2 i
which is quare root of -1 = i
and i^2 = -1

Answer 7

There are no square roots for negative variables. Sorry.

Answer 8

6a^2 i

* i is an imaginary number

Answer 9

6a^2 i