Na3PO4 · 12H20 (aq) + Zn(C2H3O2)2 · 2H2O (aq) 'arrow' Zn3(PO4)2 · 4H20 (s) + NaC2H3O2 (aq) + H2O (l)
please email me @ morganelyse08@adelphia.net if that is hard to read!
2007-05-21 14:24:26 · 4 answers · asked by Morgan 1 in Science & Mathematics ➔ Chemistry
I believe that the balanced equ. would be:
2 : 3 ----->1 : 6 : 26
These are the numbers in order.
please check my numbers, just do not copy the numbers. Count the atoms.
good luck.
2007-05-21 14:34:02 · answer #1 · answered by Anonymous · 0⤊ 0⤋
2 Na3PO4 · 12H20 (aq),
3 Zn(C2H3O2)2 · 2H2O (aq)
1 Zn3(PO4)2 · 4H20 (s),
6 NaC2H3O2 (aq)
26 H2O
2007-05-21 21:42:29 · answer #2 · answered by Anonymous · 0⤊ 0⤋
i would seperate the water of the hydrates and treat them seperately. Then you have a simple double replacement reaction to balance.
The hydrate waters have 14 moles on the left side and only 4 hydrates on the right side. So the released water will have to have a coefficient of 10.
the rest of the balancing is not difficult. Break the components into their respective ions and you can solve it.
2007-05-21 21:32:19 · answer #3 · answered by reb1240 7 · 0⤊ 0⤋
just make sure that there are an equal number of atoms on each side of the equation, and then it is balanced.
2007-05-21 21:33:07 · answer #4 · answered by sakhi93 4 · 0⤊ 0⤋