What is the molarity of acetic acid in vinegar?

Question

molarity of acetic acid in vinegar needed.

Answer 1

Vinegar is just a solution of 5% Acetic acid in water (aqueous.)

Molarity = mol/L

how many moles of acetate in 1 L?

in 1 L, 1000 ml = 1000 grams

therefore, 50 grams of Acetic Acid.

Acetic Acid is HC2H3O2, mol. weight is 60 gm/mol.

Therefore, 50/60 is 0.83, so there are 0.83 moles of Acetic Acid in 1L, so the molarity is 0.83.

You could also correctly say that "...vinegar is basically 0.8M Acetic Acid."

Answer 2

Acetic Acid In Vinegar

Answer 3

Most vinegar is 4.5% acetic acid by mass. So that's 45 grams in 1 liter of vinegar.

The molecular mass of acetic acid is 60 grams. So there is about 45/65 moles of acetic acid in 1 liter of vinegar.
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You can easily get to molarity from there.

Answer 4

Says wikipedia: "The acetic acid concentration ranges typically from 4 to 8 percent by volume for table vinegar [1] (typically 5%) and higher concentrations for pickling (up to 18%)."

So let's assume the typical of 5% (v/v). Thus in 1L of water, 50mL is acetic acid.

Acetic acid has a density of 1.049g/mL. Thus in 50mL there is:

d=m/V
1.05=x/50
x = 52.5 grams

Molar mass of acetic acid is 60.05 grams
Molarity = 52.5/60.05
= 0.87M

Done :)

Answer 5

Apple Cider Vinegar eBook - http://AppleCiderVinegar.siopu.com/?Xtb

Answer 6

acetic acid = HOAc M = molarity = moles HOAc/(L of HOAc(aq)) 1HOAc(aq) + 1KOH(aq) --> 1H2O(l) + 1KOAc(aq) moles of KOH = 0.03145 L X 0.256 mole/L = 0.0080512 From the 1:1 stoichiometry, moles of HOAc = moles of KOH = 0.0080512 M molarity of HOAc = 0.0080512 moles HOAc/0.010 L HOAc(aq) = 0.80512 M The molarity of HOAc(aq) = 0.80512 M

Answer 7

generally, your garden variety store bought vinegar is 0.85M.