∫ x^2 / x^(3)-7 dx b=3 a=2?

Answer 1

If the question is: ∫{(x^2)/[(x^3)-7]}dx, a=2 and b=3,
then the answer is (1/3)[ln(20)].


Solution:

∫{(x^2)/[(x^3)-7]}dx = (1/3)∫{3(x^2) /[(x^3)-7]}dx
= (1/3) ln [(x^3)-7]

Substituting a and b, we have,

(1/3)[ln(27-7)-ln(8-7)] = (1/3)[ln(20)-ln(1)]
=(1/3)[ln(20)].

Answer 2

Do it on your graphing calculator. It is allowed on the AP Test.
If you want the manual, and slow, way then:

(ln(3^3-7))/3 - (ln(2^3-7))/3

Answer 3

I = (1/3).∫ (3x²) / (x³ - 7) dx
I = (1/3).log (x³ - 7) + C
What are b and a?

Answer 4

Too complicated!

Hope you get the answer soon.
Good luck!