Math help?

Question

Two number cubes are tossed. Find probability (only one shows a 2).

Answer 1

You would multiply the probability of getting a two on one cube (1/6) by the probability of NOT getting a 2 on a second cube (5/6).
1/6 X 5/6 = 5/36

Hope this helps!

Answer 2

Assuming a "number cube" is a die. Then there are 6 possible numbers per die. The chance of 2 coming up on one is 1/6.
The chance of it not coming up is 5/6.
Combining these gives 1/6 x 5/6 = 5/36 probability of throwing only one "2". =0.139