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2007-05-21 13:33:28 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

I = ∫ e^(5x).dx
let u = 5x
du / dx = 5
dx = du / 5
I = (1/5).∫ e^u du
I = (1/5).e^u + C
I = (1/5).e^(5x) + C

2007-05-21 23:53:16 · answer #1 · answered by Como 7 · 0 0

(1/5)*e^(5x)

Integral(e^(n*x)dx) = (1/n)*e^(n*x)

2007-05-21 20:41:38 · answer #2 · answered by Anonymous · 0 0

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