x^3+x^2+x+1
2x^2-7x+3
3x^2-24x+48
Thanks a bunch, just wanted to make sure my answers are correct :)
2007-05-21 12:58:44 · 5 answers · asked by And kayla was like 1 in Science & Mathematics ➔ Mathematics
-1 is a root of the first one, so
(x+1)(x^2+1)
that can't be factored any more
2x^2-7x+3
this is just an in-the-head factor
(2x-1)(x-3)
3x^2-24x+48
3(x^2-8x+16)
3(x-4)^2
2007-05-21 13:05:26 · answer #1 · answered by chess2226 3 · 0⤊ 1⤋
x^3+x^2+x+1 Note that -1 is a zero so x+1is a factor
Divide x+1 into x^3+x^2+x+1 to get x^2+1.
So factors are (x+1)(x^2+1)
2x^2-7x+3
(2x -1 )(x - 3)
3x^2-24x+48
(3x - 12)(x-4) = 3(x-4)^2
2007-05-21 20:09:40 · answer #2 · answered by ironduke8159 7 · 0⤊ 1⤋
x^3+X^2+x+1
x^2(x + 1) +(x +1)
(x^2 + 1) (x +1)
2x^2-7x+3
2x^2-x-6x+3
x (2x -1) -3 (2x -1)
(x-3) (2x-1)
3x^2-24x+48
3(x^2-8x+16)
3(x^2-4x-4x+16)
3(x-4)^2
2007-05-21 20:12:53 · answer #3 · answered by The_Cookie_Goddess 3 · 0⤊ 0⤋
(x+1)(x^2+1)
(2x-1)(x-3)
3(x^2-8x+16)
3(x-4)^2
2007-05-21 20:34:04 · answer #4 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
(x+1 )(x+1 )(x+1) i believe
(2x-3)(x-1)
thats all i can do cus i got to go bye
2007-05-21 20:06:36 · answer #5 · answered by Anonymous · 0⤊ 2⤋