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I can't figure out how to do these.

Find a counterexample to show that the statement is not true.

^=square root
^a2(squared)+b2(squared)=a+b

2007-05-21 07:21:01 · 5 answers · asked by ? 1 in Science & Mathematics Mathematics

5 answers

Let [ = square root and ^ signify an exponent

[ (a^2 + b^2) = a + b
Is not true, for example
[ (0^2 + 1^2) = [1 and does not = 0 + 1
Another example
[ (4^2 + 2^2) = [ (16 + 4) = [ 20 = 2[5 does not equal 4 + 2

2007-05-21 07:28:32 · answer #1 · answered by kamcrash 6 · 0 0

is the square root around both a and b or just a?
I will assume its around both.
so a counterexample would be ^(3(squared)+4(squared))= ^(9 + 16) = ^(25) = 5
but a + b = 3+4 =7 which is not equal to 5

2007-05-21 14:30:33 · answer #2 · answered by fredorgeorgeweasley 4 · 0 0

Jeez Dewd.......... Find a counterexample. That means find 2 numbers (call them a and b) such that
√(a²+b²) is not equal to a+b.

How about 3 and 4?
√(3²+4²)=√(9+16) = √(25) = 5 and
3+4=9

HTH

Doug

2007-05-21 14:29:27 · answer #3 · answered by doug_donaghue 7 · 0 0

sqrt(a^2 + b^2) =? a +b
Let a = 1 and b=2
Then sqrt(1^2 +2^2) =? 1+2
sqrt (1+4) =? 1+2
sqrt(5) =? 3
sqrt(5) not = 3, so this counterexample shows that sqrt(a^2+b^2) = a+b is false.

2007-05-21 14:34:51 · answer #4 · answered by ironduke8159 7 · 0 0

^(-5)2(sq)+^22(sq)=29
-5+2=-3

2007-05-21 14:33:03 · answer #5 · answered by nathan r 1 · 0 0

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