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When two resistances are conn. in parallel then the equivalen resistance is6\5 .When one of the resistance is removed then the effective resistance is 2.The resistance of the wire removed will be
1. 3
2. 2
3. 3\5
4. 6\5

2007-05-21 07:18:09 · 2 answers · asked by godisgreat 1 in Science & Mathematics Physics

2 answers

Resistances in parallel have an equivalent resistance of
1/Rt = 1/R1 + 1/R2 + .........

You know that one of the resistors is 2 Ω (it says so in the problem) so you need to do some simple 9'th grade algebra to get the value of the other resistor.

HTH

Doug

2007-05-21 07:24:42 · answer #1 · answered by doug_donaghue 7 · 0 0

The answer is the first option. The resistance of the removed wire is 3.

2007-05-21 14:28:56 · answer #2 · answered by swelled 1 · 0 0

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