Integration?

0 ⤊

Integrate [sinhx/(1+(sinhx)^2)] dx

2007-05-21 06:21:07 · 2 answers · asked by colt 1 in Science & Mathematics ➔ Mathematics

I = ∫ (sinh x / cosh ² x) dx
let u = cosh x
du = sinh x.dx
I = ∫ (1/u²).du
I = ∫ u^(-2).du
I = - 1 / u + C
I = - 1 / cosh x + C
I = - sech x + C

2007-05-21 06:38:25 · answer #1 · answered by Como 7 · 0⤊ 0⤋

You can do your integrations at this website:

http://integrals.wolfram.com/index.jsp

The answer to your question is:

-cosh(x) / (1 + (sinh(x))^2 )

2007-05-21 13:35:56 · answer #2 · answered by poison_for_food 2 · 0⤊ 0⤋