2007-05-21 04:18:30 · 4 answers · asked by Whatever 1 in Science & Mathematics ➔ Mathematics
This is a right triangle. The angle in question is the one at P. The length of the opposite is y. The length of the adjacent is x. P = invtan(y/x)
2007-05-21 04:22:36 · answer #1 · answered by TychaBrahe 7 · 0⤊ 0⤋
Draw the triangle. Let the angle RQP be theta.
Cos(theta) = x/y
theta = arccos(x/y)
hence we can say that R is theta degrees north of east from Q.
2007-05-21 11:27:41 · answer #2 · answered by dudara 4 · 0⤊ 0⤋
If you draw a right triangle, it should be obvious that
cos (angle PQR) = x/y. So direction from Q to R is
N (PI/2 - arccos(x/y)) E
uk_wildcat
2007-05-21 11:28:16 · answer #3 · answered by uk_wildcat96 2 · 0⤊ 0⤋
The information is not sufficient to provide an answer. Not all combinations of x and y are valid and the result depends on latitude.
2007-05-21 11:26:03 · answer #4 · answered by ra 3 · 0⤊ 0⤋