Factor: 2x^2 - 5x + 6 = by using trial factors?

Answer 1

2x^2 - 5x + 6 =2x^2 - 3x-2x + 6 =x*(x-3)-2(x-3).
=*(x-3)(x-2)answer

Answer 2

You are looking for two numbers x and y.

x * y = 6
2x + y = -5

The problem is that this problem doesn't have real roots. You are not going to find an answer using trial factors.

Look at this part: -5x + 6. In the radical of the quadratic formula, we use sqrt(b^2 - 4 * a * c). Here that is sqrt(25 - 48), or sqrt(-23). X is an imaginary number with radical roots. (1.25 +/- sqrt(-23)/4). Personally, I would never think to try that.