b^-7b+3=0 use quadratic formula?

Question

A)+- square root of 3
B)3 and 1
C)+-7 square root of 3 over 2
D)7+- square root of 37 over 2

Answer 1

b² - 7x + 3 = 0

Quadratic formula:
[ -b ± √(b² -4ac)] / 2a

For your equation, a = 1, b = -7, c = 3

[7 ± √( (7)² - (4)(1)(3)) ] / (2)(1)

[7 ± √ (49 - 12) ] / 2

[7 ± √37 ] /2

So your answer is:
D)7+- square root of 37 over 2

Answer 2

b = [ 7 ± √(49 - 12) ] / 2
b = [ 7 ± √(37) ] / 2
ANSWER D)