2007-05-21 03:38:26 · 11 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
b^2-13b+30
=b^2-3b-10b+30
=b(b-3)-10(b-3)
=(b-3)(b-10)
2007-05-21 03:45:25 · answer #1 · answered by alpha 7 · 1⤊ 0⤋
(b+10)(b+3)
so b= -10 and b= -3
2007-05-21 03:44:04 · answer #2 · answered by Fred L 1 · 1⤊ 0⤋
b^2 - 13b + 30 = b^2 - 3b - 10b + 30
= b(b - 3) -10(b - 3)
= (b-3)(b-10)
Hence b = 3 or b = 10
2007-05-21 03:49:22 · answer #3 · answered by bach 2 · 1⤊ 0⤋
Given Equation = b^2-10b-3b+30
=b(b-10)-3(b-10)
=(b-3)(b-10)
Therefore b=3 or b=10
2007-05-21 07:22:33 · answer #4 · answered by sriram t 3 · 0⤊ 0⤋
Since the thirty is positive and the thirteen is negative, the two numbers in the ( ) would be negative. Negative times negavtive is positive. Then the only two factors of thirty that equal thirteen are 10 and 3. therefore making the answer
(b-10)(b-3)
2007-05-21 03:49:14 · answer #5 · answered by Emma Chica 3 · 1⤊ 0⤋
13b - 30 + 6 = - sixty 3 -------------- (– 30 + 6 = – 24) 13b – 24 = – sixty 3 --------- deliver – 24 on RHS it ameliorations its sign and could become + 13b = – sixty 3 + 24 13b = – 39 ----------------- (–ve No. + + ve No do subtraction and supply sign of greater desirable quantity.) b = – 39/13 = – 3 ----
2016-12-11 15:55:56 · answer #6 · answered by rushford 3 · 0⤊ 0⤋
You need two numbers that multiply to 30 and add to -13
These numbers are -10 and -3 - remember minus * minus = plus
The factors are: (x-10)(x-3) = 0
x = 10
x = 3
2007-05-21 03:45:49 · answer #7 · answered by welcome news 6 · 1⤊ 0⤋
=(b-3)(b-10)
2007-05-21 03:41:46 · answer #8 · answered by Anthony 2 · 1⤊ 0⤋
Assume equation is:-
(b - 10).(b - 3) = 0
b = 3, b = 10
2007-05-21 03:41:36 · answer #9 · answered by Como 7 · 1⤊ 0⤋
(b-10)(b-3)
2007-05-21 03:41:00 · answer #10 · answered by dark_massiah 3 · 1⤊ 0⤋