What is 3x(x+4)=2?

Answer 1

3x^2 + 12x - 2 = 0
dividing each side by 3
x^2 + 4x - 2/3 = 0
x^2 + 4x + 4 - 4 - 2/3 = 0
(x + 2)^2 - 14/3 = 0
(x + 2 + sqrt(14/3))(x + 2 - sqrt(14/3)) = 0
x = -2 -sqrt(14/3)
x = -2 + sqrt(14/3)

Answer 2

First expand the parentheses: 3x^2 + 12x = 2. Now subtract 2 from each side:

3x^2 + 12x - 2 = 0

Apply the quadratic formula where a=3, b=12, c=-2:

x = [-12 +- sqrt(144 + 24)]/6
x = -2 +- sqrt(166)/6 = -2 +- 2.147

Answer 3

3x(x+4) = 2
Expand:
3x^2 + 12x = 2
3x^2 + 12x - 2 = 0
Now use the formular:

x = -b/2a + sqrt(b^2 - 4ac)/2a OR-b/2a - sqrt(b^2 - 4ac)/2a

a = 3, b = 12 c = -2

Substituting, we have:
x = -12 /6 + sqrt(144 + 24)/6 OR -12 /6 - sqrt(144 + 24)/6

x = -2 + sqrt(168)/6 OR -2 - sqrt(168)/6

x = -2 +12.9614/6 OR -2 -12.9614/6

x = -2 +2.1602 OR -2 - 2.1602
Therefore x = 0.1602 OR -4.1602

Answer 4

3x(x+4)=2
3x^2 +12 - 2=0
dividing each side by 3
x^2 + 4x - 2/3 = 0
x^2 + 4x + 4 - 4 - 2/3 = 0
(x + 2)^2 - 14/3 = 0
(x + 2 + sqrt(14/3))(x + 2 - sqrt(14/3)) = 0
x = -2 -sqrt(14/3)
x = -2 + sqrt(14/3)

Answer 5

Expanding the right side of the equation we get

3x^2 + 12x = 2
Subtracting 2, we get
3x^2 + 12x -2 = 0
Since we cannot factor easily, we graph and find the zeroes in a calculator or we use the quadratic formula

In the end we get, x = .162278 and x = -6.16228

Answer 6

3x² + 12x - 2 = 0
x = [- 12 ± √(144 + 24)] / 6
x = [- 12 ± √(168)] / 6
x = [- 12 ± 2√42] / 6
x = - 2 ± (1/3).√42

Answer 7

distribute the equation to yield
3(x)^2 +12x = 2

subtract 2 from both sides:
3(x)^2 +12x -2 = 0

this is in the form now of
ax^2 +bx +c = 0

a=3
b =12
c=-2

Now use the quadratic formula to solve for x

[-b +/- square root (b^2 - 4*a*c)] / (2*a)

Plug and chug...

Answer 8

3x(x + 4 ) = 2
3x^ + 12x = 2
3x^ + 12x - 2 = 0
x = -4.160 or x = 0.160

^ = square