P = Perimeter.............Dimensins for ty's gardene
2007-05-21 00:40:35 · 6 answers · asked by Philip P 3 in Science & Mathematics ➔ Mathematics
Let x = width of Ty's garden
2x + 4 = length of Ty's garden
Perimeter is 72
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Required: the dimensions of the garden
Perimeter = 2 length + 2 width
72 = 2 (2x + 4) + 2x
72 = 4x + 8 + 2x
72 = 6x + 8
72 - 8 = 6x
64 = 6x
64/6 = 6x/6
10.667 = x ==> width
Length = 2x + 4
Length = 2(10.667) + 4
Length = 21.334 + 4
length = 25.334
2007-05-21 01:02:09 · answer #1 · answered by detektibgapo 5 · 0⤊ 0⤋
Length = 25 1/3 metres
Width = 10 2/3 metres
Perimeter = 72
2 x length + 2 x width = 72
2 x 25 1/3 + 2 x 10 2/3 = 72
(close enough for the Dr.Q and hence proved!!)
2007-05-21 07:52:09 · answer #2 · answered by Doctor Q 6 · 0⤊ 0⤋
Assuming the garden in rectangular in shape, then the perimeter is two lengths plus two widths. Let "w" be the width. Then the length is 2w + 4. So adding everything up, we have:
2*w + 2(2w + 4) = 72
Solve this for w to find the width, then use 2w + 4 to find the length:
w + (2w + 4) = 72/2
3w + 4 = 36
3w = 32
w = 32/3
So the width is 32/3 m and the length is 2*(32/3) + 4 = 64/3 + 12/3 = 76/3 m
2007-05-21 07:44:46 · answer #3 · answered by Anonymous · 0⤊ 2⤋
Width = w
Length = 2w + 4
2w + 4w + 8 = 72
6w = 64
w = 64/6 = 32 / 3
Width = 32/3 m
Length = 64/3 + 4 = 76/3 m
2007-05-21 11:59:29 · answer #4 · answered by Como 7 · 0⤊ 0⤋
P=2l + 2b
l=4+2b
72=2(4+2b) + 2b
=8 + 4b + 2b
6b = 64
b=64/6
=10.67m
l=4+2b
=25.33m
The garden is 25.33m by 10.67m to the nearest 0.01m
2007-05-21 07:47:38 · answer #5 · answered by gudspeling 7 · 0⤊ 0⤋
Length=2*Width+4
Perimeter=72=2L+2W
72=2(2W+4)+2W
72=4W+8+2W
72=6W+8
72-8=6W
64=6W
64/6=W
32/3=W
Length=(2*32/3)+4
Length=64/3+4
Length=(64+12)/3
Length=76/3
Width=32/3
2007-05-21 08:18:48 · answer #6 · answered by r s 2 · 0⤊ 0⤋