out of 50 students, 80% are right handed. If 30% of the left handed students are blueeyed and 12.5% of the right handed students are also blue eyed, what is the probability that (the student is right handed | the student is not blue eyed)?
2007-05-20 17:47:50 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
P(students rite handed) =80%
P(students right handed and blue eyed)=12.5% x 80% =10%
thus the P(students rite handed and not blue eyed) = 80%-10% =70%
2007-05-20 17:56:17 · answer #1 · answered by Anonymous · 0⤊ 0⤋
87.5% of the right-handed students are not blue-eyed, or 70% of the total population.
70% of the left-handed people are not blue-eyed, or 14% of the total population.
given that a student is not blue-eyed, the probability that the student is right-handed is
70/(70+14) = 70/84 = 5/6, or 66 2/3%
2007-05-20 18:04:04 · answer #2 · answered by Helmut 7 · 0⤊ 0⤋