slope-intercept form question Plz Help!!?

Question

can somebody please help me with this homework problem and solve it all the way out...actually i have 2

write the slope-intercept form of an equation of the line that passes through the given point and is parallel to the graph of each equation.

1. (2,-1), y=2x+2
2. (-5,-4), y=1/2x+4

Answer 1

1.) Parallel lines have the same slope, but differing y-intercepts. Let the slope stay the same and find a different value for b (the y-intercept) using the given x and y coordinates.

y = 2 x + b
-1 = 2 (2) + b
-1 - 4 = b
-5 = b

Check it by substituting x = 2 and b = -5 into the equation. If y = -4, then we have the right solution.

y = 2 x + b
y = 2 (2) - 5
y = 4 - 5
y = -1

So our solution is correct. The new equation is y = 2 x -5 and the point (2, -1) is located on the graph of this equation.


2.) Do the same thing here:

y = ½ x + b
-4 = ½ (-5) + b
-4 = (-5/2) + b
-4 + 5/2 = b
-8/2 + 5/2 = b
-3/2 = b

Check to make sure b is correct by substituting in x = -5 and b = -3/2. If it is correct, then y will equal -4.

y = ½ (-5) - 3/2
y = (-5/2) - 3/2
y = -8/2
y = -4

So our solution is correct. The new equation is y = ½ x - 3/2, and contains the point (-5, -4) on its graph.

Answer 2

i think the answers are:
1. y = 2x - 5
2. y = 1/2x - 3/2