2007-05-20 16:38:36 · 7 answers · asked by rose 4 in Science & Mathematics ➔ Mathematics
take 3sqrt(x) to left amd 20 to right
- sqrt(x) = - 5
sqrt(x) = 5
x = 5^2 = 25
2007-05-20 16:42:28 · answer #1 · answered by Mein Hoon Na 7 · 0⤊ 0⤋
2âx+20=15+3âx
2âx - 3âx = -20 + 15
-âx=-5
âx =5
x = (5)^2
x = 25
2007-05-20 23:42:09 · answer #2 · answered by sudhi_kandi 3 · 0⤊ 0⤋
2âx+20=15+3âx
seperate value of root x 1 side n other is 1 side
2âx -3âx =15-20
subtraction
-âx = -5
- to - cancel
squaring both side
x=25
value of x =25
2007-05-21 07:54:41 · answer #3 · answered by ANJU R 2 · 0⤊ 0⤋
25
2007-05-20 23:50:13 · answer #4 · answered by Lopa 3 · 0⤊ 0⤋
2âx+20=15+3âx
20-15=3âx - 2â3
5 = âx
25 = x
HTH
Doug
2007-05-20 23:43:06 · answer #5 · answered by doug_donaghue 7 · 0⤊ 0⤋
up there is wrong.
2root x +20 = 15 + 3rootx
3rootx over 2rootx = 20-15
rootx =5
x = the square root of 5
2007-05-20 23:44:49 · answer #6 · answered by go hokies 1 · 0⤊ 0⤋
2x^1\2-3x^1\2=15-20.
-x^1\2= -5
5=x^1\2
x=5^2
x=25
2007-05-24 09:15:40 · answer #7 · answered by srivarun 2 · 0⤊ 0⤋