Trig Help please!?

1 ⤊

verify, show work.

(sec^2x) / (tanx) = secxcscx

2007-05-20 16:21:16 · 3 answers · asked by qwerty123 1 in Science & Mathematics ➔ Mathematics

remember sec = 1/cos
tan = sin/cos

sec^2 / tan = 1/cos^2 * cos / sin = 1/cos * 1/sin
= sec * csc

2007-05-20 16:28:48 · answer #1 · answered by Dr D 7 · 1⤊ 0⤋

= (1 / cosÂ² x) X (cos x / sin x)
= 1 / (cos x) X (1 / sin x)
= sec x . cosec x

2007-05-21 04:30:59 · answer #2 · answered by Como 7 · 0⤊ 0⤋

sec(x)= 1/cos(x)
1/tan*x) = cot(x) = cos(x)/sin(x)

sec^2(x)/tan(x) = 1/cos^2(x) * cos(x)/sin(x) = 1/cos(x)sin(x)
= sec(x)csc(x)

2007-05-20 23:29:20 · answer #3 · answered by holdm 7 · 0⤊ 0⤋