How do you reduce this?

Question

(m+1)(m+2) over m(m^2+m-2)

Answer 1

this can be reduced by factoring the demoninator of the expression and then cancelling the similar terms....

the bottom factors to:
(m+2)(m-1)

you can then cancel out the m+1 term from both the top and bottom leaving you with

[(m+1) / m(m-1)]

Answer 2

In this case, the polynomial in the denominator can be factored:
(m^2+m-2) = (m+2)(m-1)

So, your problem becomes:
(m+1)(m+2) over m(m+2)(m-1)

The (m+2)'s cancel out, leaving:
(m+1) over m(m-1)

Answer 3

Factor the m(m^2+m-2).
You then get:

(m+1)(m+2) over
m(m+2)(m-1)

Cancel out the (m+2) out of the numerator and denominator.
You then get:

(m+1) over
m(m-1)

Answer 4

when you distribute, you get this:

m^2+3m+2 over m^2+m-2

then when you reduce it, you should get

m^4+4m+2

I think, not positive though