Some Algebra II Quadratics questions?

Question

What is the equation for a circle with a center of (2, -3), and a a radius of 5?

Find the midpt. of a segment with these 2 endpts. (3/5, -7/4) and (1/4, -2/5)

Answer 1

equation of a circle= (x-h)^2 + (y-k)^2 = (radius)^2
(h,k) is the center of the circle

Answer:
(x-2)^2 + (y+3)^2 = 25

Midpoint Formula=(x1+x2)/2 (y1+y2)/2

Answer:
(3/5 + 1/4)/2 (-7/4 + -2/5)/2

Simplify the fractions:
(12/20 + 5/20)/2 (-35/20 + -8/20)/2

(17/20)/2 (-43/20)/2

Answer 2

a million. you are able to in basic terms confirm the minimum fee of the variety because of the fact the area of the quadratic function is the set of genuine numbers. because of the fact that a=2 and the parabola opens upward, then the minimum fee of the variety is your ok in the vertex, that's -3. 2. vertex: (-2, -4) and axis of symmetry is x = -2, if the given function is y = 2(x+2)^2 - 4 3. a.) y = (x + 4)^2 - 26 b.) y = (x - a million)^2 + 7 4. rewriting it into vertex form: y = 2(x + 2)^2 - 18 vertex: (-2, -18); axis of symmetry: x = -2 5. a.) (-x + 6)(x + 7) b.) (x + 6)(x + 8) c.) (x - 4 )(x - 2) 6. a.) 8x(2x + a million) b.) (x + 8)(x - 8) c.) (4x + 5)(4x - 5)

Answer 3

for the circle part the answer is

(x-2)^2 + (y- -3)^2=5^2 or 25

Answer 4

1. (x-2)^2 +(y+3)^2=25
2. (17/40, -43/40)