i know it has to do sometin with substitution i just barely understand it hough
2007-05-20 12:51:45 · 5 answers · asked by andrew 3 in Science & Mathematics ➔ Mathematics
By 'do' I hope you mean 'factorise'.
Putting u^2 = x, this becomes:
x^2 - 10x + 9
giving factors of:
(x - 9)(x - 1)
Putting x = u^2, you obtain:
(u^2 - 9)(u^2 - 1)
and you can then factorise each of these as the difference of two squares, getting:
(u - 3)(u + 3)(u - 1)(u + 1).
2007-05-20 12:58:12 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Just looking at this equation, I can see that u=-1 and u=1 are solutions. That means that (u +1) and (u - 1) are factors of this equation. You can use long division to find the other solutions.
(u + 1) | (u^4 - 10u^2 + 9) = u^3 - u^2 - 9u + 9
(u - 1) | (u^3 - u^2 - 9u + 9) = u^2 - 9
(u^2 - 9) = (u - 3)(u +3)
Therefore, the solutions to the equations are +/- 1 and +/- 3.
2007-05-20 13:04:00 · answer #2 · answered by mwebbshs 3 · 0⤊ 0⤋
June 4, 1966 the year my woman got here into this international. i wasn't born on the time till 1980, yet June 4, 1966 replaced into the date my woman had come into this international, and that i thank her mom and pa for making that day possible. this woman of mine is invariably my soulmate, and that i admire the finished international out of her.
2016-12-11 15:18:45 · answer #3 · answered by Anonymous · 0⤊ 0⤋
(u^2-1)(u^2-9)
(u-1)(u+1)(u-3)(u+3)
u=+/-1 +/-3
2007-05-20 13:06:46 · answer #4 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
what do you want to do with it? factor it? find the roots?
2007-05-20 12:57:55 · answer #5 · answered by Anonymous · 0⤊ 0⤋