If you open a bottle of champagene, or fizzy beer, you get a fizz.
But it's controllable, - you just contain the excess spill-over with a napkins , or whatever.
But, if you drop a bottle of beer just before you open it, or take the cap off, - or iff you shake the bottle and then take the cork out, why, all hell breaks loose! Why?
It's a Physics conundrum I don't understand.
P1* V1 /T1 = P2*V2/T2, so why the heck does P3 (the pressure when opened) become uncontrolled?
2007-05-20 12:44:59 · 6 answers · asked by Luke Skywalker 6 in Science & Mathematics ➔ Physics
The pressure change is the same in both cases--but keep in mind that while in the container, the gas in the liquid is dissolved, the gas in the headspace of the container is, well, at the top. For the quiescent drink, when you release the pressure by opening, the gas at the top innocuosly expands out of the container, and some of the dissolved gas starts leaving the drink (fizz). By SHAKING the container prior to opening you get a MIXTURE, e.g. foam, and bubbles now cling to the inside of the container (in the liquid). Now, when you open the drink--this gas expands identically to before--but now there is beverage between it and the outside air. Result: Beverage is pushed out of the container. If you don't want to wait for the mixture and bubbles to settle out: For a non-sudsy drink (a soft drink, not beer), you can tap a shaken-up can a few times prior to opening, (I find tapping the top works best) releasing the bubbles adhering to the inside of the can, and open the drink with fewer repurcussions.
2007-05-20 16:05:13 · answer #1 · answered by supastremph 6 · 0⤊ 1⤋
Shaking the container breaks the bonds of the dissolved and absorbed gas and frees it from the clutches of the liquid.
As the container is still closed, the gas can't go anywhere but is over-excited and literally bursting to escape.
Opening the container liberates the gas pressure all at once and you have a hell of a mess.
Leave the container alone for a while, or cool it and the gas quietens down and goes back to bed in the liquid.
2007-05-20 22:51:04 · answer #2 · answered by Norrie 7 · 1⤊ 0⤋
A lot of gas is dissolved in fizzy drinks. When you drop the bottle you disturb the equilibrium with the impact, so, the gas is not dissolved anymore and wants to get out real bad. So when you open the bottle it's really violent. If you leave a bottle you have dropped for a while, it will normaly.
2007-05-20 19:51:50 · answer #3 · answered by dr_luj 2 · 0⤊ 0⤋
im a waiter. dont know about physics. all i know is that the pressure inside increases w the shock, so it has to level w the pressure outside. if the cork seal loosens, it find a tiny way out and hell breaks loose. I'd say the c0c must expand or something. when this happens w a bottle of champagne i just bring the cork closer to my ear and fight the pressure its making, letting some of the gas out slooowly. and ill listen to the fizz. when it dies out, i just pull the cork out and voila. no spill. the pressuere leveled w the outside
2007-05-20 19:58:15 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Fizzy drinks are supersaturated with CO2. The bottler bottles the drink under high pressure to cause the supersaturation equilibrium to be maintained. When you open the bottle you release that pressure and upset that equilibrium which causes the CO2 to rapidly gasify and leave the solution.
This is what happens when a person gets the "bends" from diving. Leaving high pressure of being underwater causes nitrogen to rapidly gasify out of the bloodstream.
2007-05-20 19:54:57 · answer #5 · answered by coachfolds 3 · 1⤊ 0⤋
carbon dioxide bubbles
2007-05-20 19:53:14 · answer #6 · answered by ? 4 · 0⤊ 0⤋