2007-05-20 12:36:07 · 11 answers · asked by Sarah H 1 in Science & Mathematics ➔ Mathematics
(6x²+5)-(2x-5)=(3x²-3x)
(6x²+5) - (2x-5) - (3x²-3x) = (3x²-3x) - (3x²-3x)
6x²+5 - 2x + 5 - 3x² + 3x = 0
3x² + x + 10 = 0
2007-05-20 12:41:30 · answer #1 · answered by Astral Walker 7 · 0⤊ 0⤋
you cant because if you simplify it you can get to 6x²-2x+10, and then can divide that by 3 to get 3(3x²-(2/3)x+(10/3))
but you cannot get to 3x²-3x unless you are either not in base 10, using a 3 dimensional plane, or have a specific number x that you are trying to find....
in which case you would subtract 3x² from 6x² leaving you with 3x² and then add 3x to -2x to get x...
you would then have an equation that looked like
3x²+x+10=0
so you would use the quadratic rule to factor and find the answers for x
2007-05-20 19:47:25 · answer #2 · answered by brebitz 2 · 0⤊ 0⤋
(6x²+5)-(2x-5)=(3x²-3x)
6x^2 -2x + 10 = 3x^2 - 3x
3x^2 +x + 10 = 0
2007-05-20 19:41:37 · answer #3 · answered by Steve A 7 · 0⤊ 0⤋
(6x^2+5)-(2x-5)=(3x^2-3x)
6x^2+5-2x+5 = 3x^2-3x
3x^2+x+10=0
2007-05-20 19:43:48 · answer #4 · answered by de4th 4 · 0⤊ 0⤋
Use the BODMAS rule Brackets, Order, Division, Multiplication, Addition, Subtraction
2007-05-20 19:40:41 · answer #5 · answered by Del Piero 10 7 · 0⤊ 0⤋
3x^2+x+0=0
(then plug tht into the quadratic formula)
2007-05-20 19:39:26 · answer #6 · answered by Anonymous · 0⤊ 1⤋
6x²-2x+10=3x²-3x
3x²-5x+10=0
i think.................
my head hurts
2007-05-20 19:43:23 · answer #7 · answered by :) 3 · 0⤊ 0⤋
0 = 0.
2007-05-20 19:38:10 · answer #8 · answered by Anonymous · 0⤊ 3⤋
(6x²+5)-(2x-5)=(3x²-3x)
6x^2+5-2x+5=3x^2-3x
3x^2+x+10=0
x=1/6[-1+/-sqrt(1-120)]=1/6[-1+/-sqrt(-119)]. answer
2007-05-20 19:43:08 · answer #9 · answered by Anonymous · 0⤊ 0⤋
HOLY GAGA! that makes my brain hurt....
2007-05-20 19:38:25 · answer #10 · answered by Anonymous · 0⤊ 2⤋