Chem Help please?

Question

At equilibrium a mixture of N2, H2, NH3 gas at 500 degrees celsius is determined to consist of 0.630 mol/L of N2, 0.397 mol/L of H2 and 0.136 mol/L of NH3.
What is the equilibrium constant for the reaction.

N2 (g) + 3 H2 (g) <=> 2 NH3 (g)

at this temperature?

Answer 1

K = [NH3]^2/[N2][H2]^3

K = (0.136)^2/(0.630)(0.397)^3

K = (0.0185)/(0.630)(0.0626)

K = 0.469

Answer 2

You can work with moles/L in the gas phase as well as the liquid phase.

[0.136]^2/ { [0.630][0.397]^3 }= Kp
Grind it out.