Concentration Help!!?

Question

1. 500mL of a solution contain 0.1 mole of acetic acid, HC2H3O2. The solution is diluted with water to the 1L mark. Calculate the molarity of the resulting solution.

2. What is the concentration of a solution formed by diluting 300mL of a solution containing 0.1 mole of HCL to 6L

Answer 1

1) 500mL=0.5l so in 1 L you have 0.1m/0.5 =0.2mole of acetic acid
molarity 0.2M


2) 300ml= 0.3l so the molarity is 0.3 *0.1/6 = 0.005M