Proove csc X + cot X = sin X / (1+cos X)?

Question

Proove csc X + cot X = sin X / (1+cos X)

yeah i got that 1/sin x + cos x/ sin x= (1+cos x)/1 i thought i was wrong that is why i asked cause i don't think i copied the question wrong.

Answer 1

cscx=1/sinx; cotx=cosx/sinx, then

1/sinx +cosx/sinx =(1+cosx)/ sinx, this is what I get....check your question.

Answer 2

My teacher told me we can proove the equation by starting at left side or right side of the equation.

I choose with the right side because my teacher said it's much more easier to deal with fraction.

sin X / (1 + cos X)
= sin X (1 - cos X) / (1 + cos X) (1 - cos X) (eliminate the fraction)
= sin X (1 - cos X) / (1 - cos^2 X)
= sin X (1 - cos X) / sin^2 X (sin^2 X + cos^2 X = 1)
= (1 - cos X) / sin X
= 1/sin X - (cos X/sin X)
= csc X - cot X

I'm sure the sign is negative and not positive.

Hope this can help you.

Good luck and all the best.

Answer 3

Wrong question dear. There are two ways amend this question....i.e.

i. csc X + cot X = (1+cos X) / sin X.

or

ii. csc X - cot X = sin X / (1+cos X).

Now.. tell me what are u trying to solve I can help u in your maths problems.....any time..I'll be available 4 heling u.

Answer 4

LHS
= 1 / sin x + cos x / sin x
= (1 + cos x) / sin x
which does not agree with RHS

Answer 5

cot(x) + csc(x) = sin(x) / (a million-cos(x)) He basically broke down the left fringe of the equation: cos(x)/sin(x) + a million/sin(x) [cos(x) + a million ]/sin(x) To teach they're equivalent, [a million + cos(x) ]/sin(x) = sin(x) / (a million-cos(x)) circulate multiply a million - cos^2(x) = sin^2(x) a million = cos^2(x) + sin^2(x) <-- id

Answer 6

closet X5