2007-05-20 07:36:07 · 8 answers · asked by joey b 1 in Science & Mathematics ➔ Mathematics
50x49x48= 117600 ways.
2007-05-20 07:45:14 · answer #1 · answered by gartfield72 2 · 0⤊ 0⤋
It depends on whether you can tell the people apart. If the question is how many ways 50 seats can be occupied by any 3 people regardless of who sits where, then the answer is
50!/(47! 3!) = 50 x 49 x 48/6
If it matters who sits where -- i.e., if Alice, Bob, Carl sitting in seats 1, 2, and 3 counts separately from Alice, Carl, Bob sitting in the same seats, then that gives you 6 times as many possibilities, namely 50 x 49 x 48.
2007-05-20 14:44:53 · answer #2 · answered by Astronomer1980 3 · 0⤊ 0⤋
First seat, 50 possibilities
second, 49
3rd, 48 possibilites
117600 possibilites
2007-05-20 14:39:00 · answer #3 · answered by samswebsite 4 · 0⤊ 0⤋
80 different ways, because you multiply 3 times 50.
2007-05-20 14:46:43 · answer #4 · answered by Anonymous · 0⤊ 0⤋
50! - 46! = 117600
2007-05-20 14:50:41 · answer #5 · answered by Anonymous · 0⤊ 0⤋
19600 ways if you don't care which order
117600 ways if order does matter
either way, one heck of a musical chairs game
2007-05-20 14:41:46 · answer #6 · answered by chess2226 3 · 0⤊ 0⤋
Is this a real math question or are you going to an orgy?
2007-05-20 14:39:11 · answer #7 · answered by Anonymous · 0⤊ 0⤋
117,600.
But there will still be 47 people standing âº
Doug
2007-05-20 14:40:46 · answer #8 · answered by doug_donaghue 7 · 0⤊ 0⤋