What is the frequency (in hertz) that electron turns around hydrogen atom?

Answer 1

The electron does not actually orbit the nucleus in the classical sense (like a satellite orbiting the Earth). However, if as an exercise you choose to interpret it that way, then you would derive the orbital period using the mass and charge of the proton in the nucleus to get the period of the "orbit", using electrical forces instead of gravitational.

If you do so, you will find that the orbital velocity of the electron is about c/137, where c is the speed of light. That is about 2.2e08 cm/sec.

The "classical" radius of the H atom is 0.5 Angstrom, which is 0.5e-08 cm. So the length of the orbit would be 2 pi r = 3.1e-08 cm. The orbital frequency is thus

2.2e08/3.1e-08 = 7e15 Hz

Interestingly, this is in the frequency of visible light. It is the fact that ground-state atoms do NOT emit such light that led to the development of a the quantum model of the atom.

Answer 2

First 2 are wrong + and - don't repel and the nuclear (strong) force has nothing to do with the electron Electromagnetism is what keeps the electron in orbit around the proton. The proton is in the nucleus, which is positive. The electron is negative. The electron stays in orbit Now, you may wonder why they don't just come together, well, that's quantum mechanics for you. That's the way it is. In normal physics, they come together. In quantum mechanics, the electron orbits. The electron is constantly in motion, that's how it was made in the Universe. Because of this motion, it will never come together with the proton.

Answer 3

It depends on the transitions and the observed spectral lines in the Lyman series but it is within the following boundaries (in Hz):

2.46 x 10^15 TO 3.28 x 10^15

Hope this helps.

Answer 4

well we would have to do this as a force of attraction question.

F= m v^2 /r = F(nuclear)

F = m(electron)*r*(omega) ^2 = F(nuclear)

omega = 2*pi/(frequency)

so:
f=sqrt(m(electron)*r*4*(pi^2)/ F(nuclear))
where f is the freqency.
where r is the orbital radius of the electron from the center of the atom.

Answer 5

IIRC, it's somewhere around 1.2 or 1.3 GHz.

Dig out a copy of the CRC Handbook and look it up ☺

Doug