Multiply it together. FOIL (First Inner Outer Last)
(x+1)(2x+3)
2x^2+3x+2x+3
2x^2+5x+3
Another way I learned to do it is in a box. imagine that theres a line under the 2x +3 and on the right of the x+1.
2x +3
x 2x^2 +3x
+1 +2x +3
You take this stuff and combine the like terms.
So you get 2x^2 + 5x + 3
Hope this helps [[:
2007-05-20 07:02:35
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answer #1
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answered by Anonymous
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Use the "FOIL" method
First x * 2x = 2x^2
outside x * 3 = 3x
inside 1 * 2x = 2x
last 1 * 3 = 3
add them together so
2x ^2 +3x +2x +3 =
2x^2 +5x+ 3
2007-05-20 14:01:39
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answer #2
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answered by chess2226 3
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To multiply, FOIL
First 2x*x
Outside x*3
Inside 1*2x
Last 1*3
Add them
2x^2 +3x +2x +3
2x^2 +5x +3
2007-05-20 14:02:11
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answer #3
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answered by samswebsite 4
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The acronym "FOIL" is helpful. Multiply, the first, outer, inner, and last terms and then add them all together.
First: x and 2x. Multiplied together is 2x^2.
Outer: x and 3. Multiplied together is 3x.
Inner: 1 and 2x. Multipled together is 2x.
Last: 1 and 3. Multipled together is 3.
Add them all together:
2x^2 + 3x + 2x + 3
= 2x^2 + 5x + 3
2007-05-20 14:01:06
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answer #4
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answered by Eddie K 4
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= 2x² + 3x + 2x + 3
= 2x² + 5x + 3
2007-05-20 15:45:46
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answer #5
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answered by Como 7
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(x+1)(2x+3)
=x(2x+3)+1(2x+3)
=2x^2+3x+2x+3
=2x^2+5x+3
2007-05-20 14:03:47
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answer #6
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answered by lol? 1
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