2007-05-20 06:55:50 · 6 answers · asked by kct08 1 in Science & Mathematics ➔ Mathematics
Simple
Since log m + log n = log (m/n) & log 10 =1 (all base 10),
Therefore,
log (x/5) = log (10)
Can cancel both the logs and we get,
x/5 = 10
=> x = 10*5 = 50
2007-05-20 07:36:26 · answer #1 · answered by chan_l_u 2 · 0⤊ 0⤋
First you have to look at this two properties:
1. The difference of two Log is Log A - log B= Log (A/B).
2. If Log A=c, then 10^c = A.
Then aplying this two properties and solving for x you get:
Log x - Log 5=1
Log (x/5)=1, first property.
10^1=x/5, second property,
now solve for x:
10^1=10, so x/5=10
then multiplying both sides by 5, you get:
5(x/5)=5(10)
x=50, solution.
2007-05-20 07:11:01 · answer #2 · answered by gartfield72 2 · 0⤊ 1⤋
log (x) - log (50) = 1
log (x/5) = 1
10^log (x/5) = 10^1
x/5 = 10
x=50
2007-05-20 07:02:59 · answer #3 · answered by msi_cord 7 · 0⤊ 1⤋
log x - log 5 = 1
log x - log 5 = log 10
log x = log 5 + log 10
log x = log (5*10)
log x = log 50
x = 50
2007-05-20 07:01:09 · answer #4 · answered by welcome news 6 · 1⤊ 1⤋
log x - log 5 = 1
log (x/5) = 1
x/5 = 10^1
x/5 = 10
x = 50
2007-05-20 06:58:39 · answer #5 · answered by Eddie K 4 · 2⤊ 1⤋
log(a)-log(b)=log(a/b)
so log(x)-log(5)=log(x/5)
log(a)=b<=>a=10^b
so x/5=10 => x=50
2007-05-20 07:05:11 · answer #6 · answered by Johan 2 · 0⤊ 1⤋