I'm asked to simplify the square root of: (1+x^2)
2007-05-20 06:35:09 · 12 answers · asked by kokis0394 2 in Education & Reference ➔ Homework Help
how can u simply 1+x^2?
do u mean 1+x^2=0?
then it would be no solution b/c u cant square root a negative when u subtract 1 on both sides....
2007-05-20 06:39:26 · answer #1 · answered by »SMiLEY« 4 · 0⤊ 0⤋
There's not much that can be done to simplify this expression further, except perhaps to write it as (1 + x²)^½. Another trick which could be employed is to multiply it by its conjugate on the top and bottom, but this really results in a more complex, not a simpler form. Here's what I mean:
(1 + x^2)^½ x [(1 - x^2)^½ / (1 - x^2)^½]
Which results in:
{√ [(1 + x^2)^½ (1 - x^2)^½] } / (1 - x^2)^½,
which certainly is not a simpler form.
2007-05-20 06:53:16 · answer #2 · answered by MathBioMajor 7 · 0⤊ 0⤋
I think you have to multiply by a half if you want to get rid of the square root.
2007-05-20 06:42:32 · answer #3 · answered by Anonymous · 0⤊ 0⤋
x=i OR the square root of negative one
2007-05-20 06:41:33 · answer #4 · answered by essence of falling stars 2 · 0⤊ 0⤋
It cannot be simplified any further.
2007-05-20 06:48:26 · answer #5 · answered by hersheykiss8908 2 · 0⤊ 0⤋
you divide by 2 or multiply by half
2007-05-20 06:40:26 · answer #6 · answered by prince4816 3 · 0⤊ 1⤋
1/sq.rt. x
2007-05-20 06:51:38 · answer #7 · answered by i 2 · 0⤊ 0⤋
UMM, wow I have no idea, sorry, good luck!!!
2007-05-20 06:37:17 · answer #8 · answered by samantha 3 · 1⤊ 0⤋
sqrt(1+x^2)=sqrt((1+x)^2-2x)
=sqrt((1+x)^2-(sqrt(2x))^2)
=sqrt((1+x)+sqrt(2x)) * sqrt((1+x)-sqrt(2x))
2007-05-20 07:03:45 · answer #9 · answered by sriram t 3 · 0⤊ 0⤋
i don't think it gets any simpler
2007-05-20 06:39:46 · answer #10 · answered by Dasi 2 · 0⤊ 0⤋