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The problem is y=x/1-x and to solve for x. I'm not stupid or anything (Doin college algebra and I'm in 6th grade) but I never seen this problem! How do I solve this?

2007-05-20 06:09:12 · 7 answers · asked by Harry K 1 in Science & Mathematics Mathematics

7 answers

I'm assuming you mean y=x/(1-x) because if not:

y=x/1-x
y=x-x
y=0
x would equal all real numbers

for y=x/(1-x) multiply both sides by the denominator of the right side
x=y(1-x)

2007-05-20 06:14:05 · answer #1 · answered by jsoos 3 · 0 0

The reciprocal of x/(1-x) = (1-x)/x to the negative 1 power
In other words, (1/x - 1)^-1
Therefore 1/y = (1/x - 1)
1/y + 1 = 1/x
(1+y)/y = 1/x
y/(1+y) = x

2007-05-20 13:17:04 · answer #2 · answered by Matt 2 · 0 0

x=y/(1+y)

Solution:
Multiply bs by (1-x)
(1-x)y = x

Expand
y-xy = x

Carry over
y = x + xy

Factorise
y = x(1 + y)

Divide by (1+y)
y/(1+y) = x

2007-05-20 13:21:33 · answer #3 · answered by Anonymous · 0 0

y (1 - x) = x
y - x.y = x
y = x + x.y
y = x.(1 + y)
x = y / (1 + y)

2007-05-20 15:43:18 · answer #4 · answered by Como 7 · 0 0

if you mean y=(x/1) -x,
y=x-x
y=0

if you mean y=x/(1-x),
y=(x/1) - (x/x)
y=x - 1

2007-05-20 13:19:42 · answer #5 · answered by ooh...shiny. 2 · 0 0

y = x/(1-x)
y * (1-x) = x/(1-x) * (1-x)
y - xy = x
y - xy + xy = x + xy
y = x + xy
y = (1+y) * x
y/(1+y) = x

2007-05-20 13:15:31 · answer #6 · answered by IMAO 2 · 0 0

no idea;y =0; but x?incomputable.u need another eqn.and sole simultaneously.Ask ur teacher.Or is there a misprint?

2007-05-20 13:15:22 · answer #7 · answered by Answerninator 2 · 0 0

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