Find the magnitude and direction Angle for the vector < -2,5>?

Answer 1

The angle θ is measured counterclockwise from the positive
x-axis. It can be measured with the tangent.

tanθ = y/x = -5/2
θ = arctan(-5/2) ≈ 111.80141°

The magnitude of a vector v can be calculated using the Pythagorean Theorem.

|| v || = √[(-2)² + 5²] = √(4 + 25) = √29