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3 guys go into a hotel and split a $30 room 3-ways.

Later the management decided to refund $5 and sends the bell boy up with the cash.

Since there are 3 of them, the bell boy decides to keep $2 so they can split the $3 cash easily.

So now each guy has paid $9.

Well...
9 x 3 = 27
27 + 2 = 29

Where did the other dollar go?

2007-05-20 03:40:40 · 5 answers · asked by B.C. Slasher 2 in Science & Mathematics Mathematics

5 answers

$2 must not be added to the paid amount ($27) as $2 is from the refund.
$3 should be added ro $27 as $3 id teh refunded money, hence,
27+3 = 30

Good Riddle !!!

2007-05-20 03:48:04 · answer #1 · answered by shipdada 3 · 1 1

You are adding the money that the men don't have to the money that the bellboy does have. That doesn't make any sense. Here is where all the money is: The front desk has $25. The bellboy has $2. The men have $3 among them. That's 25 + 2 + 3 = 30, which is all of the money that was originally paid. From the method you used to get $29, it's only coincidence that the numbers are even close. Suppose the bell boy decides to keep all the money and never goes to see the men at all. Then the men have still each paid $10, and the bell boy has $5 in his pocket, but that's 3*10 + 5 = 35, so where did the extra 5 dollars come from? Now we clearly see that this method makes no sense.

2007-05-20 03:52:58 · answer #2 · answered by DavidK93 7 · 1 0

Each guy paid $9 ($10-$1 refunded)=$27 collected by the hotel.
$25 was kept by the front desk, $2 by the bellboy, which equals the $27 that was paid by the customers.

2007-05-20 03:53:24 · answer #3 · answered by Zilla 2 · 0 0

Three guys paid $9.. which is $27.

The hotel has $25
The bell boy has $2

Which is a total of $27

You are adding the total the men paid to the $2 that the bellboy kept, which means that this $2 is being added twice.

2007-05-20 03:48:14 · answer #4 · answered by suesysgoddess 6 · 2 0

its very cleverly worded but
9x3 = 27
27 - 2 = 25
which is the new price they paid for the room

2007-05-20 03:47:58 · answer #5 · answered by Anonymous · 0 0

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