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3 answers

this is true, but depending on how u dig one up or plant one (the big ones) it will do just as good as a little one! if u dig one up just make sure u get enough of the already established rootball and plant it at the same depth it was planted and keep it watered for the first month or two! if ur planting one from a garden center the same holds true but u don't have to worry about the rootball thing! shock will only occur if u sever too many feeder roots.... the small hair-like ones!

2007-05-20 01:32:55 · answer #1 · answered by Robert 4 · 1 0

I think the reason is false but the logic is closer to reality. The first answer says it one way, here is another: If a plant is twice as big as another it has been growing longer and costs more. It has twice as big a root ball, in diameter, but that means it is 4 times as heavy, therefore it is much more awkward to move and requires a bigger hole. A large plant looks more like it is going to look and fills the landscape better, but it also requires much more water and attention to get it going while people tend to think it doesn't because it is so big. It takes a certain amount of courage to space out the small plants properly to leave growing space.

2007-05-20 01:43:21 · answer #2 · answered by Mike1942f 7 · 0 1

potted plants/trees will outgrow balled and burlaped ones because b&b are shocked and growth will be stunted

2007-05-20 02:34:43 · answer #3 · answered by trehugr4life 3 · 0 0

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