physics machines help??

Question

how can the mechanical advantage of an inclined plane be calculated if only the distance, not height is included?

the question is a 200N car is raised a distance of 5 meters by an effort force of 500N.
how can the MA be calculated, if MA is calculated by length of incline/height of incline?

Answer 1

For any lever, including an inclined plane, the MA, assuming no friction, is simply the ratio of input and output forces, here it's 500/200. This particular lever is of the "length multiplier" type, rather than a "force multiplier". One assumes the force is applied horizontally, since it's more than the weight. Then the angle is arctan(500/200) and the user applied the horizontal force over a 2 meter length.

Answer 2

The artwork finished in lifting the article is comparable to it is replace in gravitational potentional power. besides the shown fact that as a results of fact the gadget is barely seventy two.5% effective this means that basically seventy two.5% of the artwork it does is going into changing the gravitational ability power of the mass. for this reason: seventy two.5/one hundred * artwork finished by potential of gadget = m*g*h = 215*9.8*5.sixty 5 = 11,904.fifty 5 J for this reason: artwork finished by potential of gadget = 11,904.fifty 5/(seventy two.5/one hundred) = sixteen,420.07 J (!!!) Your working is genuine and you have the perfect suited answer as far as a results of fact the quantity is in contact. besides the shown fact that, the unit is Joules (J) no longer N (newtons). artwork required to strengthen is the ability given to the mass while it particularly is lifted no longer the rigidity utilized to the mass because it particularly is lifted.