a 200 newton car is raised 5m by an effort force of 100N.?

Question

what's the ideal mechanical advantage? effort distance? work input?

Answer 1

W = F * d
200 N * 5 m = 1000 J (Work put into System)
Einitial + W = Efinal
Total Mechanical Energy remains constant.

1000 J /100 N = 10 m (effort distance) since the Work done must be constant or else you would be getting energy for free. A decrease in the effort force means an increase in the efforct distance to maintain this.

For Work input:
It is still 1000 J done on the system.

Answer 2

The mechanical advantage is 2
The effort distance is 2*5 = 10 m
The work input is 1 kJ

Answer 3

You can't raise a 200N car with a force of 100N. You'll need 201N before it starts to move up.