How can i work out the concentration?? H2SO4+2NaOH-> 2H2O+2Na+SO4?

Question

if i originally have 100 mL of H2SO4 solution (unknown concentration)and add 400 mL water to the solution. Then take 25 mL of the diluted solution into another beaker. add NaOH with a concentration of 0.1M (0.1 mole per litre) to the 25mL solution in order to neutralise. if it takes 118 mL of NaOH to neutralise the H2SO4 solution, how can i work out the concentration of the diluted H2SO4 solution and the concentration of the original H2SO4 solution.???

Answer 1

first, to find the molarity of diluted solution, u need to use this formula:
M1V1/M2V2= n1/n2 where 1= H2SO4 and 2= NaOH

(M1)(25mL)/(0.1M)(118mL) = 1/2
M1 = molarity of diluted H2SO4 = 0.236M

to find the concentration of original H2SO4, use the formula M1V1= M2V2

total volume of diluted solution= 100mL +400mL = 500mL
(M1)(100mL)= (0.236M)(500mL)
thus M1 =1.18M

hope it will help u ....:)

Answer 2

N1V1 = N2V2

Diluted conc = 0.236 M

Original 1.18 M