Preform the indicated operations;
(x^2 - 4x + 1) - (-8x^2 + 2x - 6) - (x^2 + 3x - 5), Thanks a lot
2007-05-19 17:25:46 · 6 answers · asked by ambi565 2 in Science & Mathematics ➔ Mathematics
The minus sign outside of the parentheses on the second and third terms just mean multiply each term in the parenthesis by negative one, which yields:
x^2-4x+1+8x^2-2x+6-x^2-3x+5
=8x^2-9x+12
2007-05-19 17:38:52 · answer #1 · answered by helper 7 · 0⤊ 0⤋
distribute all the minus signs to make the equation easier to read.
(x^2 - 4x + 1) + (8x^2 - 2x + 6)+ (-x^2 + -3x + 5)
take away the parentheses and add all like terms using the number before variable (the x). like terms mean all the x^2 or x. If theres is no number before a variable, assume it is one
answer is 8x^2 +-9x+12
2007-05-20 00:34:33 · answer #2 · answered by mapacheverde 2 · 0⤊ 0⤋
(x^2 - 4x + 1) - (-8x^2 + 2x - 6) - (x^2 + 3x - 5)
= 8x^2-9x+12
2007-05-20 00:30:13 · answer #3 · answered by sahsjing 7 · 0⤊ 0⤋
(x^2 - 4x + 1) - (-8x^2 + 2x - 6) - (x^2 + 3x - 5)
x^2 - 4x + 1 +8x^2 - 2x + 6 - x^2 - 3x + 5
8x^2-9x+12
2007-05-20 00:30:56 · answer #4 · answered by Kuan T 2 · 0⤊ 0⤋
Just do it, and collect like terms.
For the x^2 term, you will have x^2+8x^2-x^2 = 8x^2
Do the same for the (x) term and the constant.
Simplify by factoring if you can.
2007-05-20 00:31:02 · answer #5 · answered by cattbarf 7 · 0⤊ 0⤋
8x^2-9x+12 (combining everything)
Use the quadratic formula:
a=8
b=-9
c=12
2007-05-20 00:34:18 · answer #6 · answered by Cool Nerd At Your Service 4 · 0⤊ 0⤋