what is the equation?

Question

What is the equation of (-2,.25),(2,4)????

Answer 1

sum of the roots
= -2.25+2.4
=0.15
product of the roots
= -2.25*2.4
= -5.4
Therefore the equation is
x^2-0.15x-5.4=0
or 100x^2-15x-540=0 (multiplying all by 100)
or 20x^2-3x-108=0 (dividing all by 5)

Answer 2

Keronida, the question was asking for an equation, not a coordinate.

To do this, you first find the slope: m = Y2-Y1 / X2-X1 which in your case would be: m = 4-0.25 / 2-(-2) = 3.75 / 4 = 0.9375

Now that you have the slope = 0.9375, you have to put it into the point slope formula:

Y-Y1 = m(X-X1)
Y-(0.25) = 0.9375(X--2)
Y = 0.9375X - 2(0.9375) +0.25
Y = 0.9375X + 2.125

Voila, you have an equation from two points.

Answer 3

Let (x1 , y1) = (-2 , .25) and (x2 , y2) = (2 , 4)

Slope, m = (y2 - y1) / (x2 - x1)
= (4 - .25) / [2 - (-2)]
= 3.75 / 4
Multiplying by 4/4 gives : m = 15 / 16

y-intercept, b = (x2*y1 - x1*y2) / (x2 - x1)
= [2*.25 - (-2)*4] / [2 - (-2)]
= 8.5 / 4
Multiplying by 2/2 gives : b = 17 / 8

The equation is therefore : y = (15/16)x + 17/8.

Answer 4

m = (4 - .25) / (2 - -2)
m = 3.75 / 4
m = 15/16

y - 4 = 15/16 (x - 2)
y = 15/16 x + 17/8

Answer 5

(-2,.25)- y= x -.65 / (2,4)- y= x + 2

Answer 6

finding the slope:
y2-y1 : x2-x1
4-25/ 2-(-2)
= -21/4.....=m
equation = (y-y1)=m(x-x1)
=y-25= -21/4(x-(-2)
= y-25=-21/4(x+2)
= y-25=-21x-42/4
4y - 100= 21x -42
4y =21x - 42+100
4y = 21x +58
y= (21x+58)/4.....Final Answer

Answer 7

y - .25 = (3.5/4)(x + 2)
4y - 1 = 3.5x + 7


3.5x - 4y +8 = 0

Answer 8

for a straight line,
(y - 4) = ((4 - 0.25)/(2 - (-2)))(x - 2)

Answer 9

(-4, 1)